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如何通过判断函数入参类型实现不同代码逻辑
更新时间: 2026-06-26 07:47
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可参考如下示例：
class Game {
}
function solve(message: number | string | boolean | Map<string, number> | Record<string, number> | Game) {
// Game：Type judgment
if (message instanceof Game) {
console.info('Game');
return;
}
// Retrieve the constructor corresponding to the parameter and convert it to a string, then extract the string
let typeStr: string = message.constructor.toString().substring(9, 12);
// Determine the type corresponding to typeStr
switch (typeStr) {
case 'Num':
console.info('number type');
break;
case 'Str':
console.info('string type');
break;
case 'Boo':
console.info('boolean type');
break;
case 'Map':
console.info('Map type');
break;
case 'Obj':
console.info('Record type');
break;
}
}
let gameVal: Game = '';
let mapVal = new Map<string, number>();
mapVal.set('width', 100);
mapVal.set('height', 100);
let recordVal: Record<string, number> = { 'wight': 100, 'score': 100 };
@Entry
@Component
struct ParamsType {
build() {
Row() {
Column() {
Button('get params type')
.onClick(() => {
solve(100);
solve('100');
solve(true);
solve(mapVal);
solve(recordVal);
solve(gameVal);
})
}
.width('100%')
}
.height('100%')
}
} 
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